Find an equation for the line that passes through the points , −1−6 and , 5−2

Answer:The equation isy = 2x/3 + 4/3Step-by-step explanation:The equation of a straight line is represented in the slope-intercept form, y = mx + cWhere c = y interceptSlope, m = change in value of y on the vertical axis / change in value of x on the horizontal axis change in the value of y = y2 - y1Change in value of x = x2 -x1y2 = final value of y y 1 = initial value of yx2 = final value of xx1 = initial value of xFrom the information given,The points through which the line passed through are −1, −6 and , 5, −2Slope, m = (y2-y1)/(x2-x1)y2 = -2y1 = -6x2= 5x1 = -1Slope, m = (-2- -6)/(5- -1)= 4/6 = 2/3To find intercept, cLet's use ( 5, −2)-2 = 2/3 ×5 + c -2 = 10/3 + cc = -2 + 10/3 = 4/3The slope-intercept equation will be y = 2x/3 + 4/3