The equation of line m is 3xβ5y=β4.What is the slope of a line that is perpendicular to line m?Enter your answer in the box.
Accepted Solution
A:
First, write your equation in slope-intercept form, or form y = mx + b: 1) Solve for 5y: 3x - 5y = -4 3x + 4 = 5y 2) Divide everything by 5: y = 3x/5 + 4/5 Now, we got it. In this line slope is 3/5 because it is multiplier for x, and, the rule is that m * p = -1 where m is the slope of the line, and p is the slope of the line perpendicular to this. 3) Now, solve there for p by plugging in value for m: p = -1/m p = -1 / (3/5) = -5/3 4) Now just write the equation in this form: y = px + b: y = -5x/3 + b This is the equation of the line perpendicular to the given one. Hope this helps!